Advanced Computer Architecture MCQs with Answers
Practice important Advanced Computer Architecture MCQs with answers and explanations.
Chapter: 34
Q781:
The radix point in the fixed-point number 16.12 is where?
A. On the left of the integer
B. On the right of the integer
C. In between digits
D. On the far right
Correct Answer:
C
Chapter: 34
Q782:
When converting 0.2410 to base 2, which binary number is produced?
A. 0.00111
B. 0.10101
C. 0.111
D. 0.01001
Correct Answer:
A
Chapter: 34
Q783:
The multiplication of 6 by 4 using binary numbers results in what decimal number?
A. 24
B. 16
C. 20
D. 30
Correct Answer:
A
Chapter: 34
Q784:
The operation of unsigned addition can result in an m+1 bit number, leading to _______.
A. Underflow
B. Overflow
C. Error
D. None of the above
Correct Answer:
B
Chapter: 35
Q785:
What is the situation called when the result of adding two m-bit numbers exceeds the capacity of an m-bit destination?
A. Overflow
B. Underflow
C. Carry Error
D. Saturation
Correct Answer:
A
Chapter: 35
Q786:
In binary addition, what equation is used to calculate the carry bit?
A. cj = xjyj + xjcj + yjcj
B. sj = xjyjcj + xjyjcj + xjyjcj + xjyjcj
C. cj = x + y
D. sj = x + y
Correct Answer:
B
Chapter: 35
Q787:
Which adder circuit feeds carry out from the previous stage to the next stage?
A. Ripple Carry Adder
B. Carry Lookahead Adder
C. Full Adder
D. Complement Adder
Correct Answer:
A
Chapter: 35
Q788:
What is the primary advantage of a Carry Lookahead Adder?
A. Faster addition
B. Less hardware complexity
C. Easy implementation
D. No carry propagation
Correct Answer:
A
Chapter: 35
Q789:
The equation for the mux output in a 2's Complement Adder/Subtractor is defined as:
A. qj = yjr + yj r
B. qj = yjr + yjr
C. qj = xjyj + yjcj
D. qj = xjyj + yjcj + cj
Correct Answer:
A
Chapter: 35
Q790:
What do G and P represent in a Carry Lookahead Adder?
A. Generate and Propagate
B. Graph and Path
C. General and Particular
D. Gain and Power
Correct Answer:
A
Chapter: 35
Q791:
Which method of multiplication uses a combination of parallel and sequential hardware?
A. Parallel Array Multiplier
B. Series Parallel Multiplier
C. Binary Multiplier
D. Fixed Multiplier
Correct Answer:
B
Chapter: 35
Q792:
How is the sign of a product determined in signed multiplication?
A. By checking the sign of the multiplier only
B. By checking the sign of both the multiplier and multiplicand
C. By the magnitude of the numbers
D. By the number of bits used
Correct Answer:
B
Chapter: 35
Q793:
What is the first step in the Booth Recoding process?
A. Start with the Most Significant Bit (MSB)
B. Start with the Least Significant Bit (LSB)
C. Initialize the quotient counter bit to 0
D. Clear the dividend register
Correct Answer:
B
Chapter: 35
Q794:
Booth Recoding can potentially increase the number of _______ due to isolated 1s.
A. Multiplications
B. Additions
C. Subtractions
D. Divisions
Correct Answer:
B
Chapter: 35
Q795:
Which type of division involves clearing the upper half of the dividend register and putting the dividend in the lower half?
A. Integer division
B. Fractional division
C. Binary division
D. Octal division
Correct Answer:
A
Chapter: 35
Q796:
What is the quotient in binary when 4710 is divided by 510?
A. 1
B. 1001
C. 10
D. 1000
Correct Answer:
B
Chapter: 35
Q797:
The result of integer division yields the quotient and the remainder in _______.
A. Upper half of dividend register
B. Lower half of dividend register
C. Quotient register
D. Condition register
Correct Answer:
A
Chapter: 35
Q798:
The condition codes in branch architecture are computed by the _______.
A. ALU
B. Multiplier
C. Adder
D. Divisor
Correct Answer:
A
Chapter: 35
Q799:
The process of division that reports an overflow involves _______.
A. Clearing the upper half of the dividend
B. Clearing the lower half of the dividend
C. Initializing the quotient counter bit
D. Clearing both halves of the dividend
Correct Answer:
B
Chapter: 35
Q800:
The complexity of a Ripple Carry Adder is _______ compared to a Carry Lookahead Adder.
A. m
B. log(m)
C. ripple carry complex
D. ripple carry simple
Correct Answer:
C