Data Communication MCQs with Answers
Practice important Data Communication MCQs with answers and explanations.
Chapter: 50
Q661:
The theoretical highest bit rate for a telephone line with a bandwidth of 3000 Hz and SNR of 3162 can be calculated using _______.
A. Nyquist formula
B. Shannon formula
C. Both Nyquist and Shannon formulas
D. Signal-to-noise ratio alone
Correct Answer:
B
Chapter: 50
Q662:
The theoretical channel capacity for a given bandwidth and SNR is calculated using _______.
A. Nyquist rate
B. Shannon capacity formula
C. Signal-to-noise ratio alone
D. Bandwidth and noise alone
Correct Answer:
B
Chapter: 50
Q663:
If the SNR is very high, what simplification can be made for the Shannon formula?
A. SNR+1 = SNR
B. SNR = 1
C. SNR + Bandwidth = Capacity
D. The formula becomes irrelevant
Correct Answer:
A
Chapter: 50
Q664:
In the case where the SNR is high, the simplified Shannon capacity formula becomes C = B * SNRdB. What does B stand for?
A. Bandwidth
B. Bit rate
C. Signal-to-noise ratio
D. Bandwidth and signal strength
Correct Answer:
A
Chapter: 50
Q665:
If the SNR for a channel is 36 dB and the bandwidth is 2 MHz, what would the theoretical channel capacity be?
A. 30 Mbps
B. 50 Mbps
C. 100 Mbps
D. 120 Mbps
Correct Answer:
A
Chapter: 50
Q666:
If a channel has a bandwidth of 1 MHz and an SNR of 63, which method is used to find the upper limit of the data rate?
A. Shannon's formula
B. Nyquist's formula
C. Both Nyquist and Shannon formulas
D. Signal-to-noise ratio alone
Correct Answer:
A
Chapter: 50
Q667:
In Example 3.41, the upper limit for the bit rate was found to be 6 Mbps. What is the selected bit rate for better performance?
A. 6 Mbps
B. 4 Mbps
C. 2 Mbps
D. 1 Mbps
Correct Answer:
B
Chapter: 50
Q668:
When using Shannon’s formula, the highest theoretical bit rate is determined by which factors?
A. Bandwidth and signal-to-noise ratio
B. Signal frequency and noise
C. Noise and bandwidth alone
D. Only bandwidth and signal level
Correct Answer:
A
Chapter: 50
Q669:
In a noisy channel, the bandwidth is 3000 Hz, and the SNR is 3162. The theoretical highest bit rate is calculated as _______.
A. 34.86 kbps
B. 50 kbps
C. 100 kbps
D. 200 kbps
Correct Answer:
A
Chapter: 50
Q670:
Which of the following is the primary limitation in achieving the theoretical channel capacity?
A. High noise levels
B. Low bandwidth
C. High signal levels
D. Low SNR
Correct Answer:
A
Chapter: 51
Q671:
What is one of the main characteristics of network performance?
A. Bandwidth
B. Routing algorithms
C. Packet size
D. Protocol layers
Correct Answer:
A
Chapter: 51
Q672:
Which of the following measures the actual data transfer rate?
A. Bandwidth
B. Throughput
C. Latency
D. Signal-to-noise ratio
Correct Answer:
B
Chapter: 51
Q673:
Bandwidth can be measured in which two units?
A. Hertz and bytes
B. Hertz and bps
C. Frames per second
D. Packets per second
Correct Answer:
B
Chapter: 51
Q674:
If the bandwidth of a line is increased from 4 kHz to 8 kHz, what happens to the data transmission rate?
A. It doubles
B. It halves
C. It remains the same
D. It decreases
Correct Answer:
A
Chapter: 51
Q675:
A network link has a bandwidth of 10 Mbps but can only send 8 Mbps. What does 8 Mbps represent?
A. Bandwidth
B. Latency
C. Throughput
D. Signal degradation
Correct Answer:
C
Chapter: 51
Q676:
What is the bandwidth in Hertz of a line transmitting data at 4 kHz?
A. 4 Hz
B. 4 kHz
C. 40 Hz
D. 40 kHz
Correct Answer:
B
Chapter: 51
Q677:
How is bandwidth in bps defined?
A. Range of frequencies
B. Number of bits transmitted per second
C. Time delay
D. Noise level
Correct Answer:
B
Chapter: 51
Q678:
Which term refers to the range of frequencies in a composite signal?
A. Throughput
B. Bandwidth in Hertz
C. Latency
D. Signal quality
Correct Answer:
B
Chapter: 51
Q679:
A link with a bandwidth of 10 Mbps can send 12,000 frames per minute, each carrying 10,000 bits. What is the throughput?
A. 12 Mbps
B. 2 Mbps
C. 10 Mbps
D. 1.2 Mbps
Correct Answer:
D
Chapter: 51
Q680:
The bandwidth of a subscriber line for data transmission using a modem is usually measured in?
A. Frames per second
B. Hertz
C. Bytes per second
D. Bits per second
Correct Answer:
D