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Data Communication MCQs with Answers

Practice important Data Communication MCQs with answers and explanations.

Multiple Choice Questions

Q2781: Fill in the blank: The process of sending an address online starts from ______.
  • A: the rightmost byte of the address
  • B: the leftmost bit of the first byte
  • C: the rightmost bit of the first byte
  • D: the middle byte of the address
View Answer
B

Q2782: Which of the following best describes the address 4A:30:10:21:10:1A?
  • A: Multicast address
  • B: Unicast address
  • C: Broadcast address
  • D: Private IP address
View Answer
B

Q2783: The hexadecimal digit 'F' in binary is:
  • A: 1110
  • B: 1111
  • C: 111
  • D: 1100
View Answer
B

Q2784: Which part of the MAC address determines the address type (unicast, multicast)?
  • A: First byte
  • B: Second digit of the first byte
  • C: Third byte
  • D: All digits
View Answer
B

Q2785: What type of Ethernet address is used when a message is to be sent to only one destination?
  • A: Broadcast
  • B: Unicast
  • C: Multicast
  • D: Anycast
View Answer
B

Q2786: Fill in the blank: A NIC card fits ______ the station and provides connectivity.
  • A: around
  • B: below
  • C: inside
  • D: near
View Answer
C

Q2787: Which network protocol is described as a broadcast network?
  • A: Ethernet
  • B: Wi-Fi
  • C: Bluetooth
  • D: ATM
View Answer
A

Q2788: What access method is used by standard Ethernet to control access to the shared medium?
  • A: CSMA/CA
  • B: CSMA/CD
  • C: ALOHA
  • D: FDMA
View Answer
B

Q2789: The term "1-Persistent" in CSMA/CD refers to:
  • A: Transmitting randomly
  • B: Transmitting after a fixed time
  • C: Transmitting immediately when the channel is idle
  • D: Transmitting after waiting some time
View Answer
C

Q2790: In Ethernet, what does CSMA/CD stand for?
  • A: Carrier Sense Medium Allocation/Collision Detection
  • B: Carrier Sense Multiple Access/Collision Detection
  • C: Channel Switch Medium Access/Collision Division
  • D: Control Sequence Mechanism Access/Data
View Answer
C

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